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12x^2-146x+246=0
a = 12; b = -146; c = +246;
Δ = b2-4ac
Δ = -1462-4·12·246
Δ = 9508
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{9508}=\sqrt{4*2377}=\sqrt{4}*\sqrt{2377}=2\sqrt{2377}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-146)-2\sqrt{2377}}{2*12}=\frac{146-2\sqrt{2377}}{24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-146)+2\sqrt{2377}}{2*12}=\frac{146+2\sqrt{2377}}{24} $
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